If tan A + B = 1 and tan A-B = 1/root3... find A and B.. Fasst!!
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Answered by
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Tan ( A + B ) = 1
So.. Tan ( A + B ) = Tan 45°
By Comparing , A + B = 45_@1
Now , Tan ( A - B ) = 1/√3
So.. Tan ( A - B ) = Tan 30°
By Comparing , A - B = 30_@2
From @1 & @2 ( On adding )
We get A = 37.5°
And B= 7.5°
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Answered by
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Heya
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Tan ( A + B ) = Tan ( 45 )
A + B = 45 .... equation ( i )
Becoz Tan ( 45 ) = 1
And
Tan ( A - B ) = Tan ( 30 )
Becoz Tan ( 30 ) = 1/√3
A - B = 30 ... equation ( ii )
Solve both the equations we get
A = 75 /2 = 37.5° And B = 7.5°
______________________________
Tan ( A + B ) = Tan ( 45 )
A + B = 45 .... equation ( i )
Becoz Tan ( 45 ) = 1
And
Tan ( A - B ) = Tan ( 30 )
Becoz Tan ( 30 ) = 1/√3
A - B = 30 ... equation ( ii )
Solve both the equations we get
A = 75 /2 = 37.5° And B = 7.5°
Similar questions
So.. Tan ( A + B ) = Tan 45°
By Comparing , A + B = 45_@1
Now , Tan ( A - B ) = 1/√3
So.. Tan ( A - B ) = Tan 30°
By Comparing , A - B = 30_@2
From @1 & @2 ( On adding )
We get A = 37.5°
And B= 7.5°