Math, asked by 2003omkaar, 1 year ago

If tan A + B = 1 and tan A-B = 1/root3... find A and B.. Fasst!!


Ishan90: Tan ( A + B ) = 1

So.. Tan ( A + B ) = Tan 45°

By Comparing , A + B = 45_@1

Now , Tan ( A - B ) = 1/√3

So.. Tan ( A - B ) = Tan 30°

By Comparing , A - B = 30_@2

From @1 & @2 ( On adding )

We get A = 37.5°

And B= 7.5°
Ishan90: Sorry I have paste it here ):
2003omkaar: Thanks Dude!!
Ishan90: Welcome

Answers

Answered by Ishan90
105

Tan ( A + B ) = 1

So.. Tan ( A + B ) = Tan 45°

By Comparing , A + B = 45_@1

Now , Tan ( A - B ) = 1/√3

So.. Tan ( A - B ) = Tan 30°

By Comparing , A - B = 30_@2

From @1 & @2 ( On adding )

We get A = 37.5°

And B= 7.5°

I hope this will help ,

If so then Mark me as brainliest :)


anonymousqueen: hii
Anonymous: yes!
Answered by Anonymous
47
Heya

______________________________

Tan ( A + B ) = Tan ( 45 )

A + B = 45 .... equation ( i )

Becoz Tan ( 45 ) = 1

And

Tan ( A - B ) = Tan ( 30 )

Becoz Tan ( 30 ) = 1/√3

A - B = 30 ... equation ( ii )

Solve both the equations we get

A = 75 /2 = 37.5° And B = 7.5°

2003omkaar: thanks mate!
Anonymous: wello☺️
2003omkaar: Hey!
Anonymous: yes!
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