Question

if tan (a-b) =1/root 3 and tan (a+b) =root3, where 0 degree is less (a+b) and a is more than b, then find a and b

Answer 1

$\tan(a - b) = \frac{1}{ \sqrt{3} } \\ \tan(a - b) = \tan(30) \\ a-b = 30$
$\tan(a + b) = \sqrt{3} \\ \tan(a + b) = \tan(60) \\ a + b = 60$
a=30+b
30+b+b=60
2b=30
b=15