Question

If tan(A-B) =1 , sec (A+B) = 2/√3, then the smallest value of B is​

Answer 1

Answer:

let tan(a-b)=tan45

Step-by-step explanation:

1. both sides tan will cancel (a+b)=45 sec(a+b)=sec30 both sides sec will Cancel so (a+b)=30 a-b=45:eq1 a+b=30:eq2 both eqs sub than " b" value will be 15/2