Question

If tan (A+B) = 13 and tan (A-B) = 13
A > B, then the value of A is​

Answer 1

Answer:

tanA=−

2

1

and tanB=−

3

1

Now

tan(A+B)=

1−tanAtanB

tanA+tanB

=

1−(−

2

1

)(−

3

1

)

−

2

1

−

3

1

=

1−

6

1

−

6

5

=

−

6

5

−

6

5

=−1

⇒A+B=tan

−1

(−1)=

4

3π

Answer 2

see attached file for your answer

thanks for answering your question

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