if tan a + b = 2 root 3 and 10 a minus b equals to 1 upon root 3 then 0 is less than or equal to a + b and a + b is less than or equal to 90 degree, A > B then find a and b
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Answered by
7
given ,
tan a+b = √3
=> tan a+b = tan 60
=> a+b = 60 ------ 1
and tan a-b = 1/√3
=>. tan a-b = tan 30
=>. a-b = 30 ------------2
by 1 and 2
a= 45 and b= 15
HOPE This WILL HELP YOU.....
tan a+b = √3
=> tan a+b = tan 60
=> a+b = 60 ------ 1
and tan a-b = 1/√3
=>. tan a-b = tan 30
=>. a-b = 30 ------------2
by 1 and 2
a= 45 and b= 15
HOPE This WILL HELP YOU.....
NEHAALK:
thank you so much
Answered by
6
tan (A+B)=√3
tan(A-B)=1/√3
A+B>=0°
A-B<=90°
A>B
we can write (1) as :
tan (A+B)=tan 60°
and (2) as :
tan (A-B)=tan 30°
A+B=60°
A-B=30°
ON SOLVING :
A=45°
B=15°
tan(A-B)=1/√3
A+B>=0°
A-B<=90°
A>B
we can write (1) as :
tan (A+B)=tan 60°
and (2) as :
tan (A-B)=tan 30°
A+B=60°
A-B=30°
ON SOLVING :
A=45°
B=15°
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