Question

if tan (a+b)=√3 & tan(a-b) = 1/√3; 0​

Answer 1

Answer:

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Step-by-step explanation:

a+b=60.....1

a-b=30.......2

so , by elimination method

it would be to 2a=30

a= 15

by putting the value of a in equation 1

b=45

Answer 2

Answer:

Given :

• tan(a + b) = √3
• tan(a - b) = 1/√3

To find : a & b

Solution :

→ tan(a + b) = √3

• tan 60° = √3

→ tan(a + b) = tan 60°

→ a + b = 60 ________(1)

→ tan(a - b) = 1/√3

• tan 30° = 1/√3

→ tan(a - b) = tan 30°

→ a - b = 30 ________(2)

Now,

• Adding both the equations (1) and (2).

→ (a + b) + (a - b) = 60 + 30

→ 2a = 90

→ a = 45

• Putting this value in (1).

→ 45 + b = 60

→ b = 60 - 45

→ b = 15

Hence, the values of a and b are 45 and 15 respectively.