If Tan(A+B)=√3 and Cot(A-B) =√3 and find the value of acute angles A&B.
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Hey man Take this!
If tan(A+B) is give equal to root3 than it's obvious that
(A+B)=60 (tan 60=root 3) ...............1
And cot(A-B) is given as equal too root 3 again
therefore, (A-B)=30 (cot 30=root 3) .....................2
Now solving equation 1 & 2,
A +B = 60
A -B = 30
we get, 2A = 90
hence, A = 45 degree
Similarly you can find B by putting the value of A i.e B = 15 degree
Gotcha!!
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