Question

If tan (a+b) =√3 and cot (a-b) =√3 find a & b

Answer 1

$\mathfrak \blue {here \: is \: you r\: answer} \\ tan(a + b) = \sqrt{3} \\ cot(a - b) = \sqrt{3} \\ \mathfrak {too \: find :a \: and \: b } \\ tan(a + b) = \sqrt{3} = 60 \degree \\ cot(a - b) = \sqrt{3} = 30 \degree \\ so.. \\ a + b = 60 \degree.....eq1 \\ a - b = 30 \degree.....eq2 \\ solve...the \: both \: equations \: \\ so.. { \boxed{a = 90a \: and \: b = 60}}$

Hope my answer will help you...

Answer 2

Answer:

A= 45 and B=15

Step-by-step explanation:

tan(a+b)=√3

tan 60 =√3,

cot(a-b)=√3

cot 30 = √3,

Now,

a+b=60............................(1)

a-b=30.............................(2)

adding eq (1) &(2)

we get,

2a=90

therefore a = 45

and b=15.