Question

If tan(A+B)=√3 and tan(A–B)= 1 √3 ;0° B, B, find A and B.
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Answer 1

Answer:

tan (A + B) = √3 ⇒ A + B = 60° ………….. (i)

tan (A – B) = 13√13 ⇒ A – B = 30° ………… (ii)

From Eqn. (i) + Eqn.(ii),

we have 2A = 90 ⇒ = 45°

From eqn. (i), A + B = 60°

45° + B = 60°

∴ B = 15

A=45° & B=15°

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