Question

if tan(A+B)=√3 and tan(A-B)= 1/√3 ;0°<A+B≤90° ; A>B , find A and B.​

Answer 1

Answer:

Hey mate here's your answer.

Step-by-step explanation:

tan(A+B)=√3

tan (A+B)=tan 60°

A+B=60° (1)

tan(A-B)=1/√3

tan(A-B)=tan 30°

A-B=30° (2)

2A=90° (adding (1) and (2))

A=45°

2B=30° (subtracting (2) from (1))

B=15°

Hope it helps you.

Please mark it as brainliest answer.