Question

If tan (A + B) =√3 and tan (A – B) =1/√3,0° < A + B ≤ 90°; A > B, find A and B.

Answer 1

tan (a + b)=√3

tan (a + b)=tan 60

a+b=60 ......eqn(1)

tan (a -b)=1/√3

tan (a -b)=tan 30

a-b=30 .....eqn(2)

solving equations 1 and 2

a=45

b=15

Answer 2

Answer:

Ans:A=45 degree, B= 15 degree

Step-by-step explanation:

A+B=60

A-B=30

=>A=45,B=15