Question

If tan (A+B) =√3 and tan (A-B) =1/√3;0°<A+B≤90° ; A>B find A and B.​

Answer 1

Answer:

Step-by-step explanation:

⇒ tan(A + B) = √3

⇒ tan(A + B) = tan60°

⇒ A + B = 60°         ...(1)

⇒ tan(A - B) = 1/√3

⇒ tan(A - B) = tan30°

⇒ A - B = 30°           ...(2)

Adding (1) and (2):

A + B = 60°

 A - B = 30°

 2A     = 90°

A = 45°,  therefore, B = 60° - 45° = 15°

Therefore, A and B are 45° and 15° respectively

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