Question

If tan (A+B) = ✓3 and TAN(A-B)=1/✓3 0° <A+B≤90° find A and B​

Answer 1

Answer:

A = 45° and B = 15°

Step-by-step explanation:

tan (A + B) = √3 = 60°

tan (A - B) = 1/√3 = 30°

A + B = 60

A - B = 30

A = 45° and B = 15°

Pls mark my answer as brainlist

Pls follow me

Answer 2

Answer:

A = 45°

B = 15°

Step-by-step explanation:

given tan (A+B) = ✓3  => A+B = 60°   ------ (1)            ( as tan 60° = √3 )

          tan (A-B) = 1/✓3  => A-B = 30°   ------ (2)         ( as tan 30° = 1/√3 )

Adding (1) & (2)

=> A+B+A-B = 60° + 30°

=> 2A = 90°

=> A = 90°/2 = 45°

substitute A=45° in (1), we get

45°+B = 60°

=> B = 60°-45° = 15°