Question

If tan (A+B)= 3 and tan (A-B)= 1/√3 0°<A+B < 90°;A>B, find A and B.​

Answer 1

Answer:

a+b=60, a-b=30 a=45 b=15

Answer 2

Step-by-step explanation:

tan(A+B)=√3

tan(A+B)=tan60

A+B=60____1

tan(A-B)=1/√3

tan(A-B)=tan30

A-B=30-----1

A+B=60

A-B=30

________

2A=90

A=90/2

A=45

A+B=60

45+B=60

B=60-45

B=15

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