If tan (A+B)=√3 and tan (A-B)=1/√3;0° <A+B <_ 90°;A>B,find A and B
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Answer:
A = 45 and B = 15
Step-by-step explanation:
tan ( A + B) = tan 60 or, A+B = 60 .....( 1 )
tan ( A - B) = tan 30 or, A-B = 30 .......( 2 )
(1) + (2) :
A + B + A - B = 60 + 30
or, 2A = 90
or, A = 45
from (1),
45 + B = 60
or, B = 60 - 45
= 15
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