if tan(A+B)=√3 and tan (A-B)=1/√3 ; 0°<angleA+B</=90° ; A>B. find A and B
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Answer:
A=45° and B=15°
Step-by-step explanation:
tan(A+B)=√3
tan(A+B)=tan60°
A+B=60°---------(1)
tan(A-B)=1/√3
tan(A-B)=30°
A-B=30°---------(2)
Adding eq.1 and eq.2,we get
A=45° and B=15°
I hope it helps you....
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