if tan (A+B)=√3 and tan (A-B)=1/√3 find A and B.
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Answer:
tan(A+B)=√3
tan(A+B)=tan60
A+B=60........(1)
tan(A-B)=1/√3
A-B=30
A=30+B
(1)➡30+B+B=60
2B=30
B=15
A=30+15
A=45
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