if tan ( A + B) = √3 and tan ( A- B) = 1/√3 find a and b.... Can we cancel tan = tan in this question??
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Given,
tan(A+B) = √3
we know,
tan60° = √3
So,
A+B = 60...(i)
Now,
tan(A-B) = 1/√3
we know,
tan30° = 1/√3
so,
A- B = 30°.....(ii)
Adding equation i and ii , we get,
2A = 90°
A = 45°
then,
B = 60° - 45°
B =15°
Lol, No we cannot cancel tan = tan. It's not the way. I have solved it. you can ask the doubts if any.
Cheers!
abc1712:
u hv equated tan A- B with tan 30 coz they are equal to 1/√3 .... Bt where the tan goes???
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