If tan( A+B ) = √3 and tan (A – B) = 1/√3 such that 00 < A+B <900, A>B
Find the value of A and B
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Answer:
a = 45
b = 15
Step-by-step explanation:
tan(a+b) = √3
tan(a+b) = tan 60
a+b = 60 ...(1)
tan(a-b) = 1/√3
tan(a-b) = tan 30
a-b = 30 ...(2)
NOW USING LINEAR EQUATION : add the 2 equations
a+b+a-b = 60+30
2a = 90
a = 45
45+b = 60; b = 15
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