Question

if tan(A+B)=√3 and tan(A-B)=1/√3 then find A and B​

Answer 1

Answer:

A=45, B=15

Step-by-step explanation:

tan(A+B)=tan 60

tan(A_B) =tan 30

A+B=60

A-B=30

_______

2A=90

_______

A=90/2=45

A=45

A+B=60

45+B=60

B=60-45

B=15

Answer 2

Step-by-step explanation:

tan(A+B)=√3

tan (A+B) = 60°

A+B = 60° --------- (1)

tan(A-B) =1/√3

tan (A-B) = 30°

A-B = 30° --------- (2)

Adding 1st and 2nd we get

2A = 90°

A = 45°

Putting value of A in 1st

A+B = 60°

45°+B = 60°

B = 15°