Question

if tan(A+B)=√3 and tan(a-b)=1/√3, where 0°B then find the value of A and B.

Answer 1

Answer:

A = 45 AND B = 15

Step-by-step explanation:

tan 60 = √3 , tan 30 =1/√3

so A+B = 60 ------1

    A-B = 30---------2

SUBTRACT EQ 1ST FROM 2ND

TEN WE GET B = 15

PUT THE VALUE OF B IN EQ 1 ST

A+B = 60

A + 15 = 60

A = 60-15

A =45