if tan (A+B) = √3 and tan (A-B) = 1/√3, where A and B are acute angles.
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Answer:
tan(A+B)=√3
tan (A+B)=60--------- 1
tan (A-B) =1/√3
tan (A-B)= 30---------- 2
by compairing
adding equation 1 and 2
tan(A+B)=60
tan(A-B)=30
------------------
2A = 90
A= 45
put A in eq 1
A+B=60
45+ B =60
B =60-45
B= 15
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