If tan( ) A B + = 3 and tan( ) A B 3 1 - = , A B > , then the value of A is
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Given tan(A+B)= √3⟹A+B=60 ° ⋯(1)
tan(A−B)= 1\√3⟹A−B=30∘ ⋯(2)
(1)+(2)⟹2A=90∘
⟹A=45∘
Put A value in (1)
⟹B=60∘ −45∘ =15∘
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