IF tan (A + B) = 3 and tan (
AB)=1/13. 0* <A + B = 90': A > B. find A and
B.
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Answer:
tan(a+b) = root3
tan(a-b)= 1/root3
We know tan 60 = root 3 and tan 30 = 1/root3
So, a+b = 60, a-b = 30
Adding the two gives
a+a+b-b=60+30
2a=90
a = 45
a+b=60
45+b=60
b=15
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