if tan(A+B) = √3 and tan (AB) =1/√3; 0°<A+B≤90°; A>B, find A and B
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Answer:
tan(A+B) = tan 60degree and tan(A-B) = 30 degree
tan cancells on both sides
A+B = 60 and A-B = 30
adding these equations we get
A+B+A-B= 90
2A= 90
A= 45 degree and B= 15
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