If tan(A − B) = √3,tan(A − B) = 1 √3 , 0 0 < A + B ≤ 900 ,A > B, then find A and B.
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1
I am not sure about answer but i am trying it
Tan ( A-B)=root 3
Tan90-30 equal to root 3
Tan 90 -45 =1
Answered by
3
Tan(A-B) = √3
Tan60° = √3
∴A-B = 60°----------------(1)
Tan(A+B) = 1/√3
Tan30° = 1/√3
∴A+B = 1/√3------------(2)
Add eq 1 and 2
A+B+A-B = 60+30
2A = 90
A = 45°
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