Question

if tan(a+b)=√3,tan(a-b)=1/√3,then find and b​

Answer 1

Answer:

tan(a+b)=root3

tan(a-b)=1/root3

tan(a+b)=tan60

tan(a-b)=tan30

a+b=60(1)

a-b=30(2)

adding (1)and (2) we get

2a=90

a=45

now ,putinga=45 in (1)

45+b=60

b=15

therefore,a=45 and b=15