Question

if tan(a+b)=√3,tan(a-b)=1,thentan6b=​

Answer 1

Answer:

1

Step-by-step explanation:

tan(a+b)=√3

Wkt, tan60° = √3

⇒ tan(a+b) = tan60

∴ a + b = 60    

tan(a-b)=1

Wkt, tan45° = 1

⇒ tan(a-b) = tan45

∴ a - b = 45

Now

a + b - ( a - b ) = 60 - (45)

⇒ a + b - a + b = 60 - 45

⇒ 2b =  15

⇒ b = 15/2

6b = 6 x b

     = 6 x 15/2

∴ 6b = 45

Now

tan6b = tan45°

tan45° = 1  

Hope this helped!