Question

if tan (A+B)=√3and tan (A-B) = 1÷√3,0<A+B<90°find A and B​

Answer 1

Answer:ey there!

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tan(A+B) = √3                                           tan(A-B) = 1/√3

tan(A-B) = tan 60°--- 1)                             tan(A-B) = tan 30°

   

                                    solving 1 and 2      

A + B = 60

A - B   = 30

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2A = 90

A = 45°

Put eq. 1) in eq. 2)

=) A+ B = 60

=) 45 + B = 60

=) B = 60 - 45

=) B = 15

so, A = 45 and B = 15

Hope this helps u ^_^