Question

if tan (a+b)=√3and tan (a-b)= 1/√3; 0°<A+B_< 90°; A>B, find a and b​

Answer 1

tan(a+b)=tan60

a+b=60

tan(a-b)=tan30

a-b=30

a+b+a-b=60+30

2a=90

a=45

Putting a=45 in a+b=60, we get:

a+b=60

45+b=60

b=60-45

b=15

Hence, a=45

b=15

Answer 2

Answer:

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