Question

If tan(A+B)=√3and tan+(A-B)1/√3; 0°<A+B<= 90°;A>BEither diagnose A and B.​

Answer 1

Answer:

A = 45⁰ B = 15⁰

Step-by-step explanation:

tan(A+B) = √3 = tan60⁰

∴ A + B = 60⁰ . . . . . (1). (∴ A + B < 90⁰)

tan(A -B) = 1/√3 = tan30⁰

∴ A - B = 30⁰ . . . . (2)

Add (1) and (2)

2A = 90⁰

∴ A = 45⁰

From (1)

B = 60⁰ - 45⁰

B = 15⁰ (∴A > B)