If tan(A+B)=√3and tan(A-B)=1/√3 find A is.
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Answer:
Step-by-step explanation:
tan(A+B)=√3 tan(A-B)=1/√3
tan(A+B)=tan60 tan(A-B)=tan30
A+B=60 A-B=30
A=60-B (equ-1) 60-B-B=30 (from-1)
60-2B=30
60-30=2B
30=2B
30/2=B
B=15
substitute the value of B in equ 1
A=60-B
A=60-15
A=45
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