Question

if tan (A+B) = 60° and tan ( A-B) =⅓; 0°< A + B <_ 90° ; A> B , find A and B

Answer 1

refer the attachment.

Answer 2

HELLO DEAR,

I think something is mistake in your questions,

Right questions is like that:-

If tan (A+B) = √3° and tan ( A-B) =⅓; 0°< A + B <_ 90° ; A> B , find A and B


tan(A+B) = √3

=> tan(A+B) = tan60°

=> (A+B) = 60°——————————(1)

AND,

tan(A-B) = 1/√3

=> tan(A-B) = 30°

=> A-B = 30°————————————(2)


from---(1) and ---(2)

We get,

A+B = 60°
A-B = 30°
————————
2A = 90°

=> A = 90/2

=> A = 45°-----put in --(1)

We get,

45+B = 60

=> B = 60 - 45

=> B = 15°




I HOPE ITS HELP YOU DEAR,
THANKS