If tan(A-B)=7÷24, tanA=4÷3 ,A&B<90, A+B=
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tanA=4÷3
therefore, A=53 ......(1)
from above calculations, putting tanB=x in the formula of tan(A-B)=(tanA-tanB)÷(1+tanA×tanB), we get x=3÷4 i.e. tanB=3÷4
therefore B=37 ........(2)
from (1)&(2)
we get: A+B = 90
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