Question

if tan(a+b-c)=1 and sec(b+c-a)=2 then find out the value of a,b and c

Answer 1

tan(a+b-c)=1
a+b-c=tan^-1(1)
a+b-c = 45°........(a)

sec(b+c-a)=2
b+c-a=60°.........(b)
by eq a and b
b=52.5°

Answer 2

Answer:

Step-by-step explanation: