if tan a + b equals to root 3 and 10 a minus b equals to 1 upon root 3 find the value of a and b
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QUESTION :
if tan (a + b) equals to root 3 and tan(a - b) equals to 1 upon root 3 find the value of a and b
ANSWER :
GIVEN :
tan(a+b)=√3
tan(a-b)=1/√3
TO FIND :
a=?
b=?
SOLUTION :
tan(a+b)=√3
but tan60=√3
so a+b=60.......1
now
tan(a-b)=1/√3
but tan30=1/√3
a-b=30......2
so by elimination method adding 1 and 2
2a=60+30
a=45°
put a in 1
b=60-(45)
=15°
hence
(a,b)={45°,15°}
NOTE :
try to simplify the answer first
and don't use double angle formulae to make it more difficult
Also the question was incorrect
it should be tan(a-b)=1/√3
not 10a-b=1/√3
if tan (a + b) equals to root 3 and tan(a - b) equals to 1 upon root 3 find the value of a and b
ANSWER :
GIVEN :
tan(a+b)=√3
tan(a-b)=1/√3
TO FIND :
a=?
b=?
SOLUTION :
tan(a+b)=√3
but tan60=√3
so a+b=60.......1
now
tan(a-b)=1/√3
but tan30=1/√3
a-b=30......2
so by elimination method adding 1 and 2
2a=60+30
a=45°
put a in 1
b=60-(45)
=15°
hence
(a,b)={45°,15°}
NOTE :
try to simplify the answer first
and don't use double angle formulae to make it more difficult
Also the question was incorrect
it should be tan(a-b)=1/√3
not 10a-b=1/√3
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