if tanθ = a/b find cosθ
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here is your answer mate.....
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tanA=p/b=a/b(a=p and b=b)
then,we find
h=a^2+b^2
now,casA=b/h=b/a^2+b^2
so,cosA=a^2+b
hope it will helps,
mark me as a brainlist
then,we find
h=a^2+b^2
now,casA=b/h=b/a^2+b^2
so,cosA=a^2+b
hope it will helps,
mark me as a brainlist
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