If tan = a/b find sin2 + cos2
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If tanθ=
b
a
then the value of bcos2θ+asin2θ is
Medium
Solution
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Correct option is B)
tanθ=
b
a
⇒1+tan
2
θ=sec
2
θ⇒1+(
b
a
)
2
=sec
2
θ⇒
b
2
a
2
+b
2
=sec
2
θ⇒cos
2
θ=
a
2
+b
2
b
2
⇒
cosθ=
a
2
+b
2
b
2
we know that, sinθ=
1−
a
2
+b
2
b
2
=
a
2
+b
2
a
2
Now, bcos2θ+asin2θ=b(cos
2
θ−sin
2
θ)+a(2sinθcosθ)=b(
a
2
+b
2
b
2
−
a
2
+b
2
a
2
)+a(2
a
2
+b
2
ab
)
=
b
2
+a
2
1
[b
3
−a
2
b+2a
2
b]=
b
2
+a
2
b
3
+a
2
b
=
b
2
+a
2
b(b
2
+a
2
)
=b
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