Question

if tan (a+b)=root 3 & tan (a-b)=0,find sin(a+b) and cos (a-b).

Answer 1

Answer:

root 3/2 and 1

Step-by-step explanation:

tan(a+b) = tan 60 > a+b = 60

tan(a-b) = tan 0 > a-b = 0 > a = b

so,, a= b = 30

sin(a+b) = sin(30+30)= sin 60 = root 3/ 2

cos (a-b) = cos(30-30) = cos 0 = 1