if tan(a-b)=root 3 and tan (a-b)=1/root 3 find a and b
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exercise 1.3 question 6
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tan(a-b) = √3
--> a-b = 60° ------(i)
Also,
tan(a-b) = 1/√3
--> a-b = 30° ------(ii)
There cannot be 2 values for the same LHS.
1.Considering (a+b = 60°)
Then a = 45 , b = 15
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