Question

If tan(a+b) = root 3 , tan(a-b) = 1, then find the value of tan6b

Answer 1

Answer:

tan 6B = tan45 = 1

Explanation:

i )tan(A+B) = √3

=> tan(A+B) = tan60°

=> A+B = 60° -----(1)

ii ) tan(A-B) =1

=> tan(A-B) = tan 45°

=> A-B = 45° ----(2)

Subtract (2) from (1) , we get

2B = 15°

=> 3(2B) = 3(15°)

=> 6B = 45

Therefore,

tan 6B = tan45 = 1

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