Question

if tan = a/b show that (asin - bcos)/(asin + bcos) = (a2 - b2)/(a2 + b2)
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Given;

tan=a/b

=sin/cos=a/b

=sin=a

=cos=b

Now;

(asin-bcos)(asin+bcos)

=(a*a-b*b)(a*a+b*b)

=(a^2-b^2)(a^2+b^2)=RHS

proved.

                                                                                                                                   

Step-by-step explanation:

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