Question

if tan ( A - B ) =
$1 \div \sqrt{3}$
and tan ( A - B ) =
$1$
find A​

Answer 1

Question:

Two tangent values are given. Find A.

• $\sf{tan(A+B)=1}$

• $\sf{tan(A-B)=\dfrac{1}{\sqrt{3} } }$

Solving the Question

If we compare to the trigonometry table,

• $\sf{A+B=45}$°
• $\sf{A-B=30}$°

After solving the system equation,

• $\sf{A=\dfrac{75}{2} }$ degrees
• $\sf{B=\dfrac{15}{2} }$ degrees

For your information,

when 0°

• sin: 0
• cos: 1
• tan: 0

when 30°

• sin: 1/2
• cos: √3/2
• tan: √3/3

when 45°

• sin: √2/2
• cos: √2/2
• tan: 1

when 60°

• sin: √3/2
• cos: 1/2
• tan: √3

when 90°

• sin: 1
• cos: 0
• tan: undefined

Answer 2

Answer:

obesliy a=a+tan«Qkaro