if tan(a+b)=underroot3 and tan a=1 then find angle b
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Answer:
tan(a+b)=√3
tan(a+b)=tan60°
a+b=60°-------(1)
And,tana=1
So,a=45°
Put 'a' in (1):-
45°+b=60°
b=15°
Hence,the angle b is 15°.
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