If tan a + cot a = 2 find the value of tan^2 a + cot ^2 a
Answers
Answered by
0
Answer:
2
Step-by-step explanation:
Put a = 45°
since tan 45° = cot 45° = 1
tan² a + cot² a = 1² + 1² = 2
2 is the correct answer.
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Answered by
0
Answer:
2
Step By Step Explaination:-
tan a + cot a = 2
Squaring Both the sides we get
(tan a + cot a)^2 = (2)^2
Therefore:
tan^2 a + cot^2 a + 2×(cot a)×(tan a) = 4
As we Know (cot a) = [1/tan a]
Thus
tan^2 a + cot^2 a + 2×(1/tan a)(tan a) = 4
tan^2 a + cot^2 a + 2 = 4
tan^2 a + cot^2 a = 4-2
tan^2 a + cot^2 a = 2
Therefore the answer to the question is = 2
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