Question

if tan A + cot A = 2, prove that tan³A + cot³A = 2​

Answer 1

Step-by-step explanation:

$(a + b) ^{3} = {a}^{3} + {b}^{3 } + 3ab(a + b)$

Answer 2

Answer:

$\tan( \alpha ) + \cot( \alpha ) = 2 \\ cubing \: on\: both \: \: sides \\ \tan {}^{3} \alpha + \cot {}^{3} \alpha + 3(2) = 8 \\ \\ \tan{}^{3} \alpha + \cot{}^{3} \alpha = 2$