Math, asked by jayandnadar, 1 month ago

If tan a + cot a = m. then : tan⁴a + cot⁴a =
(a) m-4m²2
(b) m + 4m? - 2
lem-4m2 - 2 (d) 44m2 + 2

Answers

Answered by 9997627182

1

Solution:

Solution:

Given Equation in tan A+cotA=4.

On squating both sides, we get =tan^2A+cit^2A+2tanAcotA=16

,=tan^2A+cot^2A+2*tanA(1/tanA) =16

tan ^2A+cot^2A+2=16

tan^2A+cit^=16-2

tan^2A+cot^2A=14.

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