If tan a + cot a = m. then : tan⁴a + cot⁴a =
(a) m-4m²2
(b) m + 4m? - 2
lem-4m2 - 2 (d) 44m2 + 2
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Solution:
Solution:
Given Equation in tan A+cotA=4.
On squating both sides, we get =tan^2A+cit^2A+2tanAcotA=16
,=tan^2A+cot^2A+2*tanA(1/tanA) =16
tan ^2A+cot^2A+2=16
tan^2A+cit^=16-2
tan^2A+cot^2A=14.
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