if tan A+ cot B=2 A=45 degree and B is an acute angle then find the value of B
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Answered by
9
Step-by-step explanation:
tan A + cot B = 2
a =45 °
tan45 ° = 1
1+ cot B =2
cot B = 2-1
cotB =1
cot B = cot 45°
hence B =45°
Answered by
0
Answer:
B=45degree
Step-by-step explanation:
tanA+ cotB=2
<A=45°
we know that tan45°= 1
now , according to statement
1+cotB=2
cotB=2-1
cotB=1
so, angle B = 45°
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