Question

If tan A=cot B, prove that A +B= 90°.​

Answer 1

Answer:

here is your answer

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Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

tan A = cot(90°-A)

So, tan A = cot B becomes,

cot (90°-A) = cot B

Eliminating the funtion(cot),

We get,

90°-A= B

90°-A-B= 0

-A-B = -90°

-(A+B) = -(90°)

A+B = 90° (Cancellation of negative sign)

Hence proved