Math, asked by srijalsingh456, 10 months ago

If tan A=cot B, prove that A + B = 90°3​

Answers

Answered by rajsingh24
1

Answer:

answer is

Step-by-step explanation:

tan A = cot B ------------ ( eq. i)   { given }

also, tan A = cot ( 90 - A ) ------------ ( eq.ii )   { complimentary angle }

From eq. i & ii -

  cot B = cot ( 90°- A )

⇒ B = 90° - A.

⇒ 90 ° = A + B.

⇒ A + B = 90 °. [ PROVED ] .

I hope it's a helpful for you thank you.

Answered by Anonymous
2

Step-by-step explanation:

Given : tan A = cot B

Identity : tan θ = cot (90° - θ)

Here, θ = A

→ cot (90° - A) = cot B

From this, we get

→ 90° - A = B

→ A + B = 90°

Hence, proved !!

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