If tan A=cot B, prove that A + B = 90°3
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Answered by
1
Answer:
answer is
Step-by-step explanation:
tan A = cot B ------------ ( eq. i) { given }
also, tan A = cot ( 90 - A ) ------------ ( eq.ii ) { complimentary angle }
From eq. i & ii -
cot B = cot ( 90°- A )
⇒ B = 90° - A.
⇒ 90 ° = A + B.
⇒ A + B = 90 °. [ PROVED ] .
I hope it's a helpful for you thank you.
Answered by
2
Step-by-step explanation:
Given : tan A = cot B
Identity : tan θ = cot (90° - θ)
Here, θ = A
→ cot (90° - A) = cot B
From this, we get
→ 90° - A = B
→ A + B = 90°
Hence, proved !!
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